Question

The length of a rectangular field is 8xsquare + 20x.If the width is twice the length. What is the area of the field

Answer 1

Answer:

2(8x^2 + 20x)^2

Step-by-step explanation:

length = (8x^2 + 20x)

width = 2× length = 2 ×(8x^2 + 20x)

now put the values on formula,

area of rectangle = L × B

= (8x^2 + 20x) × 2 ×(8x^2 + 20x)

= 2(8x^2 + 20x)^2 Ans....