The length of a rectangular field is greater than it's width by 4m. If the perimeter of the field is 32m, find its area.
Answers
Answered by
10
Let the length be l
And width be b
So according to the question :
l = b + 4
Perimeter of rectangle = 2 ( l + b )
2 ( b+4 + b ) = 32
2 ( 2b + 4 ) = 32
2b + 4 = 16
2b = 12
b = 6
l = b + 4
l = 6 + 4 = 10
Area = l × b = 10 × 6 = 60
So area = 60m^2
Hope it helps you.
And width be b
So according to the question :
l = b + 4
Perimeter of rectangle = 2 ( l + b )
2 ( b+4 + b ) = 32
2 ( 2b + 4 ) = 32
2b + 4 = 16
2b = 12
b = 6
l = b + 4
l = 6 + 4 = 10
Area = l × b = 10 × 6 = 60
So area = 60m^2
Hope it helps you.
udit43:
Your welcome
Answered by
5
Hey here is your answer...
Let the length of the rectangular field (x + 4)m and it's width be x..
as we know that..
2(length+ breadth) = 32m
2(x + 4 + x) = 32
2(2x + 4) = 32
2x + 4 = 16
2x = 12
x = 6
x = 6
Therefore length is (6 + 4) = 10 and breadth is 6
Area of rectangular field
Length × breadth
10 × 6
60m^2
I HOPE IT WILL HELP YOU
thnx for asking Ur questions ✌️✌️
Let the length of the rectangular field (x + 4)m and it's width be x..
as we know that..
2(length+ breadth) = 32m
2(x + 4 + x) = 32
2(2x + 4) = 32
2x + 4 = 16
2x = 12
x = 6
x = 6
Therefore length is (6 + 4) = 10 and breadth is 6
Area of rectangular field
Length × breadth
10 × 6
60m^2
I HOPE IT WILL HELP YOU
thnx for asking Ur questions ✌️✌️
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