Question

the length of a rectangular field is twice it's breadth.if the perimeter of the field is 228 meters, find the dimensions of the field. ​

Answer 1

Answer:

l = 76 b = 38

Step-by-step explanation:

let breadth be x

then length = 2x

perimeter = 228

2(l+b) = 228

2(x+2x) = 228

2(3x) = 228

3x = 114

x = 38

length = 76 m and breadth = 38 m

Hope Youll Understand^_^

Answer 2

Given :-

The length of a rectangular field is twice it's breadth.

Perimeter of the field = 228 m

To Find :-

The length of the field.

The breadth of the field.

Analysis :-

Take the breadth as a variable and since the length is twice the breadth represent it as two times the breadth.

Using it's respective formula, substitute the variables and get it's values.

Substitute the value of the variable in the length in order to get both the dimensions.

Solution :-

We know that,

• l = Length
• b = Breadth
• p = Perimeter

Let the breadth be 'x', then the length would be '2x'

By the formula,

$\underline{\boxed{\sf Perimeter \ of \ rectangle=2(Length+Breadth)}}$

Given that,

Length (l) = 2x

Breadth (b) = x

Perimeter (p) = 228 m

Substituting their values,

$\sf 228 = 2 (2x + x)$

$\sf 228=2(3x)$

$\sf 228 = 6x$

Finding the value of x,

$\sf x=\dfrac{228}{6}$

$\sf x=38$

Breadth = 38 m

Length = 2x

= 2 × 38 = 76 m

Therefore, the dimensions are 76 × 38 m²