The length of a rectangular field is twice its breadth if the perimeter of the field is 288 m find the dimensions of the field
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Answered by
90
let breadth of field is X
so its length will be 2X
given, perimeter of field is 288 m ----(1)
we know that
perimeter of rectangle =2(length+breadth) ----(2)
combine (1) and (2)
2(2X+X) = 288
4X+2X = 288
6X = 288
X = 288÷6
X = 48
so breadth of field is 48 m
its length is 2X = 2×48 = 96 m
so its length will be 2X
given, perimeter of field is 288 m ----(1)
we know that
perimeter of rectangle =2(length+breadth) ----(2)
combine (1) and (2)
2(2X+X) = 288
4X+2X = 288
6X = 288
X = 288÷6
X = 48
so breadth of field is 48 m
its length is 2X = 2×48 = 96 m
Answered by
18
2(l+b)
2(x+2x)=288
2×3x=288
6x=288
X=48
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