Question

The length of a rectangular field is twice its breadth. If the area of the rectangular field is 98 sq. m., then what is the perimeter of the field? Also find the approximate length of the diagonal of the field

Answer 1

Answer:

Let breadth be = x m

Length = 2x m

Area of rectangular field = 98 sq.m

Or L × B = 98

2x × x = 98

2x² = 98

x² = 49

x = 7

So , breadth = 7m

length = 14m

perimeter of rectangular field = 2(l+b)

= 2 ( 7+ 14 )

= 42 m

Lenght of diagonal = 15.6 m (approx.)

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Answer 2

Answer:

let, breadth of rectangle= x

then, length of rectangle=2x

area of rectangular field= length×breadth

=x×2x=98

=2x^2=98

=x^2=98/2=49

=x^2= 49

=x=√49=7

breadth of rectangle=7m.

length of rectangle= 2×7=14m.

perimeter=2(7+14)

=42m.

diagonal of rectangular field

By Pythagoras theorem

(diagonal)^2=7^2+14^2

=245

diagonal=√245

=15.652