Question

The length of a rectangular field is twice its breadth. If the perimeter of the field is 228 meters. Find the dimensions of the field.

Answer 1

Answer:

length = 76 m

breadth = 38 m

Step-by-step explanation:

length = 2 (breadth)

perimeter = 2(l + b)

228 = 2(2b + b)

228 = 6b

b = 38 m

length = 2 * 38

= 76 m

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Answer 2

Dimensions of rectangular field are:-

• Length is 76 m.
• Breadth is 38 m.

Step-by-step explanation:

To find:-

• Dimensions of field.

Solution:-

Given that,

• Length of rectangular field is twice it's Breadth.
• Field is in rectangular field.
• Perimeter of rectangular field is 228 m.

Let, Breadth of rectangular field be x.

And, Length of rectangular field is 2x.

Perimeter of rectangle = 2(Length + Breadth)

➝ 228 = 2(2x + x)

➝ 228 = 4x + 2x

➝ 228 = 6x

➝ 228/6 = x

➝ 38 = x

Or,➝ x = 38

Verification:-

➝ 288 = 2(2x + x)

• Put x = 38

➝ 228 = 2(2 × 38 + 38)

➝ 228 = 2(76 + 38)

➝ 228 = 152 + 76

➝ 228 = 228

Hence, Verified!!

Dimensions are:

We have taken, Breadth be x. Thus, Breadth of rectangular field is 38 m.

We have also taken, Length be 2x = 2×38 = 76. So, Length of rectangular field is 76 m.