the length of a rectangular field is twice its breadth if the perimeter of the field is 288 M find the dimensions of the field
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let the breadth of rectangular field = x
length of rectangular field = 2x
2(l+b) = 288
2( 2x + x ) = 288
2 × 3x = 288
6x = 288
x = 288/6 = 48
breadth = 48m
length = 2 × 48 = 96m
length of rectangular field = 2x
2(l+b) = 288
2( 2x + x ) = 288
2 × 3x = 288
6x = 288
x = 288/6 = 48
breadth = 48m
length = 2 × 48 = 96m
Answered by
4
HELLO FRIEND HERE IS THE soluTION .
Let the length be 'l. And the breadth be 'b'
AQ
L =. 2b
Perimeter of the rect. =2(l+b )
288 =. 2( 2b + b )
288/2 = 3 b
144 =. 3b
B =. 48 m.
Since B is 48 m
L = 2x 48
L = 96
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