Question

The length of a rectangular filed is twice its breadth.If the perimeter of the field is 228 metres, find the dimensions of the field...​

Answer 1

Answer:

let the breadth be x m

length= 2*breadth=2x m

perimeter=228m

2(l+b)=228m

2x+x=114m

3x=114m

x= 38m

breath=38m

length=76m

Step-by-step explanation:

Answer 2

$\huge{\underline {\underline {\mathfrak{Question:-}}}}$

The length of a rectangular filed is twice its breadth.If the perimeter of the field is 228 metres, find the dimensions of the field.

$\huge{\underline {\underline {\mathfrak{Solution:-}}}}$

$Let \: the \: breadth \: of \: the \: field \: be \: x \: metres.Then, \: its \: length = 2x \: metres.$

$∴Perimeter \: of \: the \: filed = 2(length + breadth) = 2(2x + x) \: metres = 6x \: metres.$

$So, \: 6x = 228 = ) \: x = \frac{228}{6} \: [dividing \: both \: sides \: by \: 6]$

$= ) \: x = 38.$

$Hence, \:breadth \: of \: the \: filed = 38 \: metres, \: and$

$length \: of \: the \: field = (2 \times 38) \: metres = 76 \: metres.$

$\huge{\red{\ddot{\smile}}}$