Question

The length of a rectangular floor is 5 m longer than its width. If the perimeter of the floor is 86m.
find the dimensions of the floor.​

Answer 1

Answer:

perimeter of rectangle= 2(l+b)

86=2(5+b)

86=10+2b

86-10=2b

76=2b

b=76/2

b=38

so, dimensions of the floor is 38

Answer 2

Solution:-

Let:-

The length of rectangular floor be l . And its breadth be b .

According to the question, we have

Length of rectangular floor (l) = 5 + b

Given perimeter = 86 m

we know that ,

Perimeter of rectangle = 2 (l + b)

= > 86 = 2 ( l + b)

=> 86 = 2 ( 5+b + b)

=> 86 = 2 (5 + 2b)

=> 86/2 = 5 + 2b

=> 43 = 5 + 2b

=> 38 = 2b

=> 38/2 = b

=> 19 = b

Now:-

l = 5 + b = 5 + 19 = 24

Therefore:-

The length and breadth of the rectangular floor are 24m and 19 m.