Question

The length of a rectangular floor is 5 m longer than its width. If the perimeter of the floor is 563
find the dimensions of the floor
please tell full explanation​

Answer 1

Given -

The length of a rectangular floor is 5 m longer than its width. If the perimeter of the floor is 563m.

To find -

• Dimensions of the floor

Solution -

Let the width of rectangular floor be x and its length be (x + 5)

• Perimeter of the floor = 563 m

According to the question

→ 2(length + breadth) = 563

→ 2(x + 5 + x) = 563

→ 2(2x + 5) = 563

→ 4x + 10 = 563

→ 4x = 563 - 10

→ 4x = 553

→ x = 553/4

→ x = 138.25 m

•°• Width of the rectangular floor = x

= 138.25 m

•°• Length of the rectangular floor = x + 5

= 143.25m

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Answer 2

${\rm{\underline{\underline{Question:-}}}}$

❖  The length of a rectangular floor is 5 m longer than its width. If the perimeter of the floor is 563  . find the dimensions of the floor

${\rm{\underline{\underline{Given:-}}}}$

❖  The length of a rectangular floor is 5 m longer than its width.

❖ Perimeter of rectangular floor = 563 m

${\rm{\underline{\underline{To \; Find :-}}}}$

❖ Dimensions of the floor

${\rm{\underline{\underline{Solution:-}}}}$

→ Let the width be $x$

  then length will be $x + 5$

→ As , we know that

Perimeter of a rectangle = 2( length + breadth)

$\sf Perimeter\;of\;rectangle\;=2(x+x+5)m\\\\\rightarrow 563 = 2(x+x+5)m\\\\\rightarrow 563 = 2(2x+5)m\\\\\rightarrow 563 = 4x +20 m \\\\\rightarrow 563 - 20 = 4x \\\\\rightarrow 4x = 543 \\\\\\\rightarrow x = \dfrac{543}{4} \\\\\\ \rightarrow x = 138.25$

→ Let's find out the dimensions by substituting the values !!

Width = x = 138.25m

Length = x + 5 = 138.25 + 5 = 143.25

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All Done !! :D