Math, asked by nikku51101, 5 months ago

The length of a rectangular floor is 5m longer than its width. If the perimeter of the floor is 86m, find the dimensions of the floor.​

Answers

Answered by akzcreations
0

Answer:

Length= 24m, Breadth= 19m

Step-by-step explanation:

Let the width of field= x

so, length= x+5

Given in the equation:

Perimeter of the field= 2(L+B)

86= 2(x+5+x)

86= 2(2x+5)

86= 4x+10

4x= 86-10

4x= 76

x= 76/4

x= 19

Length= x+5: 19+5= 24m

Breadth= x: 19m

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Answered by simran7539
6

Solution

Given :-

  • The length of a rectangular floor is 5 m longer than its width.
  • The perimeter of the floor is 86 m .

To Find :-

  • The dimensions of the floor.

Step-by-Step-Explaination :-

Let the breadth of the rectangular floor be x m.

Then, its length = (x+5) m

As we know that :-

Perimeter of rectangle = 2 ( l + b )

According to the condition,

=> 2 [ ( x + 5 ) + x ] = 86

=> 2 ( x + 5 + x ) = 86

=> 2 ( 2x + 5 ) = 86

=> 4x + 10 = 86

=> 4x = 86 - 10

=> 4x = 76

=> x = 76/4

=> x = 19

Hence,

The dimensions of the rectangular are :-

x = 19 m

x + 5 = 19 + 5 = 24 m

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