Question

The length of a rectangular floor of 5 little longer than width if the perimeter of the floor is 86 metre find the dimensions on the floor

Answer 1

Answer:

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Step-by-step explanation:

Let the length of rectangular floor be l and its breadth be b .

According to the question, we have

Length of rectangular floor (l) = 5 + b

Given, perimeter = 86 m

we know that ,

Perimeter of rectangle = 2 (l + b)

=> 86 = 2 ( l + b)

=> 86 = 2 ( 5+b + b)

=> 86 = 2 (5 + 2b)

=> 86/2 = 5 + 2b

=> 43 = 5 + 2b

=> 38 = 2b

=> 38/2 = b

=> 19 = b

Now,

l = 5 + b = 5 + 19 = 24

∴ The length and breadth of the rectangular floor are 24m and 19m.

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Answer 2

Correct Question :

The length of a rectangular floor of 5 m longer than width if the perimeter of the floor is 86 metre find the dimensions on the floor .

Given :

• Length of Rectangular Floor is 5 m longer than its width .
• Perimeter of Rectangle is 86 m.

To Find :

• Dimensions of Rectangle.

Solution :

$\longmapsto\tt{Let\:Width=x}$

As Given that Length of Rectangle is 5 m more than its Width. So ,

$\longmapsto\tt{Length=x+5}$

Using Formula :

$\longmapsto\tt\boxed{Perimeter\:of\:Rectangle=2(l+b)}$

Putting Values :

$\longmapsto\tt{86=2(x+5+x)}$

$\longmapsto\tt{\cancel\dfrac{86}{2}=2x+5}$

$\longmapsto\tt{43=2x+5}$

$\longmapsto\tt{43-5=2x}$

$\longmapsto\tt{38=2x}$

$\longmapsto\tt{x=\cancel\dfrac{38}{2}}$

$\longmapsto\tt\bf{x=19}$

Value of x is 18 ..

Therefore :

$\longmapsto\tt{Length=19+5}$

$\longmapsto\tt\bf{24\:m}$

$\longmapsto\tt\bf{Breadth=19\:m}$