Question

The length of a rectangular floor of 5 metal longer than with it is its parameter of the floor is 86 find the the democracies of the floor

Answer 1

Answer:

Answer:

Given: length = width+5

Perimeter = 86m

To find: Dimensions of the floor

Step-by-step explanation:

Let length be 'l' and width be 'w'

According to the question,

l=w+5

Perimeter =2(length +breadth)

86=2(w+5+w) (we are writing length as w+5)

86=2(2w+5)

86/2 = 2w+5

43 = 2w+5

43-5 = 2w

38= 2w

38/2 =w

19= w.

Length =w+5

19+5

24.

Therefore, length is 24m and breadth or width is 19m

Answer 2

Perimeterofrectangle=2(length+breadth)

According to question ,

\begin{gathered}: \implies{ \sf{Perimeter = 86}} \\ \\ : \implies{ \sf{2 [(x + 5) + x ] = 86}} \\ \\: \implies{ \sf{2 (x + 5 + x ) = 86}} \\ \\ : \implies{ \sf{2 (2x + 5)= 86}} \\ \\ : \implies{ \sf{4x + 10= 86 }} \\ \\ : \implies{ \sf{4x = 86 - 10}} \\ \\ : \implies{ \sf{4x = 76 }} \\ \\ : \implies{ \sf{x = \frac{76}{4} }} \\ \\ : \implies{ \boxed{ \tt{x = 19}}}\end{gathered}

:⟹Perimeter=86

:⟹2[(x+5)+x]=86

:⟹2(x+5+x)=86

:⟹2(2x+5)=86

:⟹4x+10=86

:⟹4x=86−10

:⟹4x=76

:⟹x=

4

76

:⟹

x=19

∴The dimension soft here rectangular floor are19m and(19+5)m=24m.