Question

The length of a rectangular floor us 6m longer its width . If the perimeter of the floor is 52 m , find the dimensions of the floor.

Answer 1

perimeter = 2(L+B)

according to the question

L= 6+B

so 52 = 2(6+B+B)

6+2B= 26

2B= 20

B= 10

L=16

so the dimension = 16x10= 160

Answer 2

let width=x then length=x+6
perimeter=52
2(x+6+x)=52
2x+6=26
x=10