The length of a rectangular garden is 7 feet longer than its width. If the garden's perimeter is 182 feet, what is the area of the garden in square feet?
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let the width of Rectangle be y
so length will be y+7
2(L+B)=182
(2y+7)=91
2y=84
y=42 feet
x=42+7=49 feet
so length will be y+7
2(L+B)=182
(2y+7)=91
2y=84
y=42 feet
x=42+7=49 feet
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Answer: The area of rectangular field is 918 ft.²
Step-by-step explanation:
Let the width of rectangular garden be x
the length of rectangular garden= x + 7
Perimeter of rectangular garden field = 2( l + b )
= 2 ( x + x + 7 )
Given perimeter of rectangular garden field = 182 ft.
Therefore,
⇒ 2 ( x + x + 7 ) = 182
⇒ 2x + 7 = 61
⇒ 2x = 61 -7 = 54
⇒ 2x = 54
⇒ x = 54/2 = 27
the width of rectangular garden = 27 ft.
the length of rectangular garden= 27 + 7 = 34 ft.
Area of rectangular garden = length x width = 27 x 34 = 918 ft.²
Hence, area of rectangular field is 918 ft.²
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