Math, asked by utkarsha33380, 6 months ago

The length of a rectangular hall is 3 metres more than double of its breadth. If its perimeter is
60 metres, what is its length?​

Answers

Answered by pandaXop
58

Length = 21 m

Step-by-step explanation:

Given:

  • Length of rectangular hall is 3 metre more than double its breadth.
  • Perimeter of a rectangular hall is 60 m.

To Find:

  • What is its length ?

Solution: Let breadth be x . Therefore

➟ Double of breadth = 2x

➟ Length = 3 m more than 2x

➟ Length = (2x + 3)

As we know that

Perimeter of Rectangle = 2(Length + Breadth)

A/q

  • Perimeter is 60 m.

\implies{\rm } 60 = 2(2x + 3 + x)

\implies{\rm } 60 = 2(3x + 3)

\implies{\rm } 60 = 6x + 6

\implies{\rm } 60 – 6 = 6x

\implies{\rm } 54 = 6x

\implies{\rm } 54/6 = x

\implies{\rm } 9 = x

So, measure of

  • Breadth is x = 9 m
  • Length is 2x + 3 = 2(9) + 3 = 21 m

[ Verification ]

  • 60 = 2(21 + 9)
  • 60 = 60

\large\bold{\texttt {Verified }}

Answered by Anonymous
97

Given:

  • Length of the Rectangle hall is 3m more than it's Breadth.

  • Perimeter of Rectangle = 60m

Find:

  • Length of the Rectangle

Solution:

 \sf \star  \red{Let, \: breadth \: of \: hall = xm}

 \sf \star  \blue{so, \: length \: of \: hall = 2x + 3m}

We, know that

 \sf \to \purple{ Perimeter \: of \: rectangle = 2(l + b)}

where,

  • Perimeter of Rectangle = 60m
  • Length of Rectangle = 2x + 3m
  • Breadth of Rectangle = x m

So,

 \sf \to \pink{ Perimeter \: of \: rectangle = 2(l + b)}

 \sf \implies \pink{ 60= 2(2x + 3+ x)}

 \sf \implies \pink{ 60= 2(3x + 3)}

 \sf \implies \pink{ 60= 6x + 6}

 \sf \implies \pink{ 60 - 6= 6x}

 \sf \implies \pink{ 54= 6}

 \sf \implies \pink{x =   \cancel{\dfrac{54}{6}}= 9m}

 \sf \implies \pink{x = 9m}

\underline{\footnotesize{\sf So, length \: of \: rectangle = 2x + 3 = 2(9) + 3= 18 + 3 = 21m}}

\underline{\footnotesize{\sf and \: breadth \: of \: rectangle = x = 9m}}

_________________

Verification

Perimeter of Rectangle = 2(l+b)

\to \orange{\sf 2(21+9) = 60}

\to \orange{\sf 2(30) = 60}

\to \orange{\sf 60 = 60}

L.H.S = R.H.S

Hence, Verified

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