Question

The length of a rectangular hall is 4 metres more than its breadth. If the perimeter of the hall is 56 metres, find its length and breadth.​

Answer 1

$\huge\underbrace\mathcal\pink{anSwer}$

Let, breadth of the hall be b

then length of the hall = (b+4)

Perimeter = 2(b + b+4)

=> 56 = 2(2b + 4)

=> 28 = (2b+4)

=> 24 = 2b

=> 24/2 = b

=> b = 12

Length = b + 4 = 12 + 4 = 15 m

breadth = b = 12 m

Answer 2

$\huge{ \underline{ \bf{Given \: : }}}$

• Length of the rectangle hall is 4 metres more than its breadth
• perimeter of the hall is 56 meters

$\huge{ \underline{ \bf{To \: Find \: : }}}$

• Length and breadth

$\huge{ \underline{ \bf{Solution \: : - }}}$

Let the breadth of the hall be

• x

And let the length of the hall be

• x + 4

As we know,

Perimeter of a rectangle

$\red{ \underline{ \underline{ \boxed{ \tt{ \green{Perimeter = 2(length + breadth)}}}}}}$

$\tt \to56 =2(x + (x + 4))$

$\tt \to \cancel \frac{56}{2} = x + x + 4$

$\tt \to28 = 2x + 4$

$\tt \to2x = 28 - 4$

$\tt \to2x = 24$

$\tt \to \: x = \cancel \frac{24}{2}$

$\tt \to \: x = 12$

Therefore,

• Breadth = 12m
• Length = (x + 4) = 12 + 4 = 16m