Math, asked by Anonymous, 4 months ago

The length of a rectangular hall is 4 metres more than its breadth. If the perimeter of the hall is 56 metres, find its length and breadth.​

Answers

Answered by ItzFranklinRahul
3

\huge\underbrace\mathcal\pink{anSwer}

Let, breadth of the hall be b

then length of the hall = (b+4)

Perimeter = 2(b + b+4)

=> 56 = 2(2b + 4)

=> 28 = (2b+4)

=> 24 = 2b

=> 24/2 = b

=> b = 12

Length = b + 4 = 12 + 4 = 15 m

breadth = b = 12 m

Answered by dibyangshughosh309
44

 \huge{ \underline{ \bf{Given \:  : }}}

  • Length of the rectangle hall is 4 metres more than its breadth
  • perimeter of the hall is 56 meters

 \huge{ \underline{ \bf{To \:  Find \:  : }}}

  • Length and breadth

 \huge{ \underline{ \bf{Solution \:  :  - }}}

Let the breadth of the hall be

  • x

And let the length of the hall be

  • x + 4

As we know,

Perimeter of a rectangle

 \red{ \underline{ \underline{ \boxed{ \tt{ \green{Perimeter = 2(length + breadth)}}}}}}

 \tt \to56 =2(x + (x + 4))

 \tt \to \cancel \frac{56}{2}  = x + x + 4

 \tt \to28 = 2x + 4

 \tt \to2x = 28  - 4

 \tt \to2x = 24

 \tt \to \: x = \cancel  \frac{24}{2}

 \tt \to \: x = 12

Therefore,

  • Breadth = 12m
  • Length = (x + 4) = 12 + 4 = 16m
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