Question

The length of a rectangular lot is 5 meters more than twice its width. If the perimeter is 100 meters, what are the dimensions of the of the lot?
A.10 m by 40 m
B.15 m by 35 m
C.10 m by 15 m
D.15 m by 40 m

Answer 1

Answer:

The answer is L=36.66. B=15.833

Step-by-step explanation:

Let the breadth be=x

The length be= 2x+5

Perimeter=2(l+b)

A to Q

100=2(2x+5+x)

100=6x+5

95=6x

x=95/6

x=15.833

L=2x+5

l=36.66

B=x

B=15.833

Answer 2

Answer:

given that perimeter of rectangular field = 100m

perimeter of rectangular field formula =2(l+b)

given condition is length of a rectangular field is 5 m more than twice it's breadth or width

let breadth of the rectangular field = x

length of the rectangular field = 2x+5

perimeter of the rectangular field =100

2(l+b) =100

2(2x+5+x) =100

2(3x+5) =100

3x+5=100/2

3x+5=50

3x=50-5

3x=45

x=45/3=15

breadth of rectangle =15

length of the rectangle = 2x+5

=2(15) +5

=30+5=40

therfore L=40m and B=15m