the length of a rectangular lot is two feet less than 3 times the width. if the area of the lot is 65 ft2 find its dimensions.
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Answer:
5 and 13
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Step-by-step explanation:
Let width be x
length: 3x-2
Area = (3x-2)×x = 65
3x²-2x =65
3x²-15x+13x-65=0
3x(x-5)+13(x+5)=0
(x-5)(3x+13)=0
x-5=0
x = 5
put 5 in length's equation
3(5)-2 = 13
Well Dimension of rectangle are 5 and 13
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