Question

The length of a rectangular mural is 2 m greater than the width. The area is 20 square meters. Find the dimensions of the mural.​

Answer 1

Given:

• The length of a rectangular mural is 2 m greater than the width.
• The area is 20 square meters.

To Find:

• Find the dimensions of the mural.

Solution:

$\rightarrow \sf Let \: l \: be \: the \: length \: of \: mural \\ \sf \: and \: b \: be \: \: the \: breadth.$

$\sf \: l + 2 = b \\ \sf area = lb = 20 \\ \sf \: by \: adding \: value \: of \: b \: in \: area \\ l(l + 2) = 20 \\ {l}^{2} + 2l - 20 = 0$

$/sf \: Roots \: will \:be\: 1+ \sqrt{21} or -1- \sqrt{21}$

therefore length will be 1+underoot 21