The length of a rectangular park exceeds its breadth by 17 metres. If the perimeter of
the park is 178 metres, find the dimensions of the park.
Let the breadth of the park be x metres
Answers
Given:
The length of a rectangular park exceeds its breadth by 17 meters.
The perimeter of the park is 178 meter.
Find:
Length and breadth of the rectangular park
Solution:
Let the length of the park be 'L' m.
Let the breadth of the park be 'B' m.
The length of a rectangular park exceeds its breadth by 17 meters.
=> L = B + 17 ........(i).
We know that,
The perimeter of rectangular park = 2(L + B)
=> 178 = 2(L + B)
=> 178 = 2(B + 17 + B)
=> 178 = 2(2B + 17)
=> 178 = 4B + 34
=> 178 - 34 = 4B
=> 144 = 4B
=> 144/4 = B
=> 36 = B
The Breadth of the park is 36 m
Putting the value of B in equation (i).
=> L = B + 17
=> L = 36 + 17
=> L = 53
The Length of the park is 53 m.
Hence, the length is 53 and breadth is 36 of the rectangular park.
I hope it will help you.
Regards.
Answer:
=> (4x + 6)/(5x + 6) = 6/7
=> 7(4x + 6) = 6(5x + 6)
=> 28x + 42 = 30x + 36
=> 28x - 30x = 36 - 42
=> -2x = -6
=> x = -6/-2
=> x = 3
Step-by-step explanation: