The length of a rectangular park is 700 m and it's breadth is 300 m two cross roads each of width 10m cut the center of a rectangular park and are to it's sides find the area of roads also find the area of park excluding the area of cross roads
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Answer:
200100 sq. m
Step-by-step explanation:
length = 700 m
breadth = 300 m
area of first road = L * B
= 700 m * 10 m
=7000 sq. m
area of second road = L * B
= 10 m * 300 m
=3000 sq. m
area of roads = 7000 sq. m + 3000 sq. m - (cross roads)
= 10000 sq. m - (s * s)
= 10000 sq. m - (10 m * 10 m)
= 10000 sq. m - 100 sq. m
= 9900 sq. m
area of park = L * B
= 700 m * 300 m
= 210000 sq. m
area of park excluding cross roads = area of park - area of cross roads
= 210000 sq. m - 9900 sq. m
= 200100 sq. m