The length of a rectangular park is thrice it's breadth if the perimeter of the park is 168 m find the dimensions
Answers
Answered by
267
Hi ,
Let the dimensions of the
rectangular park are
Breadth = b m
Length ( l ) = 3b m
According to the problem given,
Perimeter of the park ( P ) = 168 m
2 ( l + b ) = 168 m
2 ( 3b + b ) = 168
2 × 4b = 168
8b = 168
b = 168/8
b = 21 m
But ,
l = 3b
= 3 × 21
l = 63 m
Therefore ,
Park dimensions are ,
l = 63 m , b = 21 m
I hope this helps you.
:)
Let the dimensions of the
rectangular park are
Breadth = b m
Length ( l ) = 3b m
According to the problem given,
Perimeter of the park ( P ) = 168 m
2 ( l + b ) = 168 m
2 ( 3b + b ) = 168
2 × 4b = 168
8b = 168
b = 168/8
b = 21 m
But ,
l = 3b
= 3 × 21
l = 63 m
Therefore ,
Park dimensions are ,
l = 63 m , b = 21 m
I hope this helps you.
:)
Answered by
135
Hey friend,
Let breadth be x
And length 3x
Perimeter given = 168m
Perimeter of rectangle = 2 ( l + b)
A.T.Q
2 ( l + b) = 168
By putting value of length and breadth, we get,
2 (3x + x) = 168
=> 2(4x) = 168
=> 4x = 168/2
=> x = 84/4
=> x = 21
Breadth = x = 21 cm
Length = 3x = 3(21) = 63
Hope it helps.
Let breadth be x
And length 3x
Perimeter given = 168m
Perimeter of rectangle = 2 ( l + b)
A.T.Q
2 ( l + b) = 168
By putting value of length and breadth, we get,
2 (3x + x) = 168
=> 2(4x) = 168
=> 4x = 168/2
=> x = 84/4
=> x = 21
Breadth = x = 21 cm
Length = 3x = 3(21) = 63
Hope it helps.
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