Question

the length of a rectangular park is twice its breadth. if the perimeter of the park is 168 meters, find its dimensions​

Answer 1

Answer:

l = 56 m, b = 28 m

Step-by-step explanation:

l=2b

P = 168

We know that P = 2(l+b)

∴ 168 = 2(2b + b) = 2(3b) = 6b

∴ b = 168/6 = 28

∴ l = 2b = 2 x 28 = 56

Answer 2

Step-by-step explanation:

$\sf \underline{Answer : - }$

Given:-

• Let the breadth (b) be b and length (l) be 3b
• Perimeter of park = 168 m

According to the question,

2(l+b)=168

2(3b+b)=168

8b=168

b=168/8

b=21 m

now,

length (l)= 3b =3×21=63 m

therefore,

Dimensions of park are length = 63 m and breadth= 21 m......