Question

The length of a rectangular play ground is 10 metres more than twice its width. If the perimeter of the play ground is 200 metres, what is its length?​

Answer 1

Answer:

55 m

Step-by-step explanation:

Given that,

The length of a rectangular play ground is 10 metres more than twice its width.

Let, the width be x m.

Therefore, we will get,

=> Length = (x+10) m

Now, it's given that,

Perimeter of the play ground = 200 m

But, we know that,

Perimeter of rectangle = 2(length+width)

Therefore, we will get,

=> 2(x + x + 10) = 200

=> 2x + 10 = 200/2

=> 2x + 10 = 100

=> 2x = 100 - 10

=> 2x = 90

=> x = 90/2

=> x = 45

Therefore, we have,

=> x + 10 = 45+10 = 55

Hence, the required Length is 55 m.

Answer 2

Answer:

70 m

Step-by-step explanation:

let length =L AND breadth =B

PERIMETER=200m

2(L +B)=200

BUT GIVEN LENGTH=2(BREADTH) +10

2(2B + 10 + B)= 200

2(3B + 10)=200

6B +20= 200

B=30

AND L= 2B+ 10

2*30 + 10=70 ANSWER