Math, asked by Shibo5089, 10 months ago

The length of a rectangular playground is 105 metre and its breadth is 40 metre along this playground on all four sides there is 3.5 metre broad road surrounding the ground what is the area of the road

Answers

Answered by Anonymous
1

Answer:

1064m^{2}

Step-by-step explanation:

Area of playground ABCD = 105m X 40m = 4200m^{2}

Width of surrounding road = 3.5m

Length PQ = RS including the road = 105m + 3.5m + 3.5m = 112m

Breadth PS = RQ including the road = 40m + 3.5m + 3.5m = 47m

Area PQRS including the road = 112m X 47m = 5264m^{2}

Area of road = Area PQRS - Area ABCD

= 5264m^{2} - 4200m^{2}

= 1064m^{2}

Attachments:
Answered by devdassonavane1978
0

Answer:

1064 sq m

Step-by-step explanation:

  • area of ABCD=105×40=4200 sq m

  • length of PQRS=105+3.5+3.5=112
  • breadth of PQRS=40+3.5+3.5=47

  • area of road= PQRS-ABCD
  • =5264-4200=1064sq m

  • ans=1064 sq m
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