the length of a rectangular plot is 20 m more than its breadth if the cost of fencing the plot @ 26.50 that is Rs 5300 what is the length of the plot in metres
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let the breath be _b
so the length would be_ b+20
perimeter of rectangle = 2(l+b)
=2(b+20+b)
=2(2b+20)
=2*(2b)+2*20
=4b+40
so fencing this whole perimeter would be = 26.5(4b+40)
=106b +1060
so 106b +1060=5300
106b=5300-1060
106b=4240
b=4240/106
b=40
so the length =b+20
= 40+20
=60
so the length would be_ b+20
perimeter of rectangle = 2(l+b)
=2(b+20+b)
=2(2b+20)
=2*(2b)+2*20
=4b+40
so fencing this whole perimeter would be = 26.5(4b+40)
=106b +1060
so 106b +1060=5300
106b=5300-1060
106b=4240
b=4240/106
b=40
so the length =b+20
= 40+20
=60
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