the length of a rectangular plot is 9m less than twice its breadth find the dimension of the plot if its perimeter is 156 m
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Let the width be a m
Length = 2a - 9 m
Perimeter = 156
=> 2(a+2a-9) = 156
=> 3a - 9 = 78
=> 3a = 87
=> a = 29
Width = 29 m
Length = 49 m
Length = 2a - 9 m
Perimeter = 156
=> 2(a+2a-9) = 156
=> 3a - 9 = 78
=> 3a = 87
=> a = 29
Width = 29 m
Length = 49 m
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let breadth of rectangular plot be x m
length=2(x-9)
perimeter=2(l+b)
156 =2(x+2x-18)
156 = 6x-18
6x=156+18
6x=174
x=174/6
x=29m
length=2(x-9)
perimeter=2(l+b)
156 =2(x+2x-18)
156 = 6x-18
6x=156+18
6x=174
x=174/6
x=29m
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