Question

The length of a rectangular wooden board is thrice its width. If the width of the board is 120 cm, find the cost of framing it at the rate of AED.5 for 20 cm.

Answer 1

Step-by-step explanation:

let the width be 120

length be 3*120

360

perimeter 2(l+b)

2(360+120) =480*2= 996

996/20

Answer 2

$\huge{\mathfrak{\purple{\underline{\underline{\orange{CORRECT\:QUESTION:-}}}}}}$

The length of a rectangular wooden board is thrice its width. If the width of the board is 120 cm, find the cost of framing it at the rate of $5 for 20 cm.

$\huge{\mathfrak{\red{\underline{\underline{\green{TO\: FIND:-}}}}}}$

• Length of Rectangular board
• Breadth of Rectangular board
• Price of framing it .

$\huge{\mathfrak{\blue{\underline{\underline{\pink{SOLUTION:-}}}}}}$

Width of board = 120cm

A.T.Q.

Length = 3 × breadth

Length = 3 × 120cm

Length = 360cm

Since, we have to frame it we need to find it's perimeter.

$\large{\boxed{\mathbb{\red{PERIMETER\:=\:2(L+B)}}}}$

$\mapsto{\bold{Perimeter\:=\:2(360+120)}}$

$\mapsto{\bold{Perimeter\:=\:2(480)}}$

$\mapsto{\boxed{\mathtt{\color{aqua}{Perimeter\:=\:960cm}}}}$

Cost of framing 20cm = $5

Cost of framing 1cm = $\frac{5}{20}$= $0.25

Cost of framing 960cm = 960 × 0.25

=> $ 240