the length of a rectangular wooden board is thrice its width . if the width of the board is 20 cm find the cost of framing it at the rate for 5 rupees for 20 cm
Answers
Answered by
3
Width = 20cm
Length = 3× width
Length = 3×20=60 cm
================
Perimeter of board = 2(length + breadth)
Perimeter of board = 2(20+60)
Perimeter of board = 2(80)=160 cm
Cost of framing = 160/20 ×5
Cost of framing = 8×5=₹40
:-)
Length = 3× width
Length = 3×20=60 cm
================
Perimeter of board = 2(length + breadth)
Perimeter of board = 2(20+60)
Perimeter of board = 2(80)=160 cm
Cost of framing = 160/20 ×5
Cost of framing = 8×5=₹40
:-)
Nandani1111:
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Answered by
4
Given,
Breadth = 20 cm
Length = 3 x Breadth = 3 x 20 cm = 60 cm.
Perimeter of Rectangle = 2 ( Length + Breadth )
= 2 ( 20 cm + 60 cm )
= 2 ( 80 cm )
= 160 cm.
The framing is done the edges of any thing and perimeter is sum of all edges.
∵ The cost of framing 20 cm is Rs. 5
∴ Cost of framing 1 cm will be Rs. 5 / 20 = Rs. 1/4.
∴ Cost of framing 160 cm will be Rs. ( 1 x 160 ) / 4 = Rs. 40
Your answer is Rs.40.
Breadth = 20 cm
Length = 3 x Breadth = 3 x 20 cm = 60 cm.
Perimeter of Rectangle = 2 ( Length + Breadth )
= 2 ( 20 cm + 60 cm )
= 2 ( 80 cm )
= 160 cm.
The framing is done the edges of any thing and perimeter is sum of all edges.
∵ The cost of framing 20 cm is Rs. 5
∴ Cost of framing 1 cm will be Rs. 5 / 20 = Rs. 1/4.
∴ Cost of framing 160 cm will be Rs. ( 1 x 160 ) / 4 = Rs. 40
Your answer is Rs.40.
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