Question

The length of a reebangle is 10 m more
than its breadth. If the permi meter of
thectangle is 80 m, kind the dimensions'est
the rectangle.​

Answer 1

$\sf\large\underline\blue{Let:}$

$\sf{\implies The\:breadth\:_{(rectangle)}=x}$

$\sf{\implies The\: length\:_{(rectangle)}=x+10}$

$\sf\large\underline\blue{To\: Find:}$

$\sf{\implies The\: Dimensions\:_{(rectangle)}=?}$

$\sf\large\underline\blue{Solution:}$

• To calculate the dimensions of rectangle at first we have to assume that the breadth of rectangle be x and the length of rectangle be x+10 then applying the formula of perimeter to calculate the value of x then find out the dimensions of rectangle:]

$\tt{\implies Perimeter\:_{(rectangle)}=2(length+breadth)}$

$\tt{\implies Given,\: perimeter=80m}$

$\tt{\implies 2(x+10+x)=80}$

$\tt{\implies 2(2x+10)=80}$

$\tt{\implies 2x+10=40}$

$\tt{\implies 2x=40-10}$

$\tt{\implies 2x=30\implies x=15}$

$\sf\large{Hence,}$

$\sf{\implies The\:breadth\:_{(rectangle)}=15m}$

$\sf{\implies The\: length\:_{(rectangle)}=25m}$

Answer 2

Answer:

Question - The length of a rectangle is 10 m more than its breadth. If the perimeter of the rectangle is 80 m, find the dimensions of the rectangle.

Answer :

Given -

• Perimeter = 80 m.

let the length of the rectangle be 10 + x (as the length is 10m more than its breadth).

And let the breadth of the rectangle be x.

→ 2(l + b) = 80

→ (10 + x + x) = 80/2

→ 2x + 10 = 40

→ 2x = 40 - 10

→ x = 30/2

→ x = 15 cm.

• Breadth = 15 cm
• Length = 10 + x = 10 + 15 = 25 cm

Therefore, the dimensions of the rectangle are 15cm and 25 cm.