Question

the length of a rod as measured in an experiment was found to be 2.48m,2.46m,2.49m,2.50m and 2.48m. Calculate (i) absolute error in each measurement (ii) mean value (iii) mean absolute error (iv) relative error (v) percentage error and (vi) express the result in proper form

Answer 1

Answer:

average length= (2.48 + 2.46 + 2.49 + 2.50 + 2.48)/5 =2.482.

absolute error = 2.48 - 2.482 = |0.002|

2.46 - 2.482 = |0.022|

2.49 - 2.482 = |0.008|

2.50 - 2.482 = |0.018|

2.48 - 2.482 = |0.002|

% error = relative error* 100 = mean absolute error / mean error

= [ (0.002) + (0.022) + (0.008) + (0.018) + (0.002) ] / 2.482

= (0.042) / 2.482 = 0.0169 (approx. value)

now % error = 0.0169*100 = 1.69%

Explanation:

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