The length of a room exceeds its breadth by 8 cm. If each had been increased by 2 cm, the area would have been increased by 60 sq. cm. (Steps to be shown please)(Please answer fast!!!!! Its urgent!!!) Its the question of class 7 book umber magic pleaseeeeeeee answer it!!!!!!!!!!!!!!
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let the breadth of rectangle be x
therefore length=x+8
area of rectangle=length× breadth
=(x+8) ×x
=x^2+8x
if both are increased by 2
length become x+10
breadth become x+2
area of rectangle=length×breadth
=(x+10) (x+2)
=x^2+10x+2x+20
=x^2+12x+20
x^2+12x+20 > x^2+x
(x^2+12x+20)-(x^2+8x) =60
x^2+12x+20-x^2-8x=60
4x+20=60
4x=40
x=40/4
x=10
the breadth of rectangle is 10 cm
therefore length=x+8
area of rectangle=length× breadth
=(x+8) ×x
=x^2+8x
if both are increased by 2
length become x+10
breadth become x+2
area of rectangle=length×breadth
=(x+10) (x+2)
=x^2+10x+2x+20
=x^2+12x+20
x^2+12x+20 > x^2+x
(x^2+12x+20)-(x^2+8x) =60
x^2+12x+20-x^2-8x=60
4x+20=60
4x=40
x=40/4
x=10
the breadth of rectangle is 10 cm
Faiqa93:
I'm sorry but your answer is wrong
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