Question

the length of a room is 1 and half times of its breadth the cost of carpeting the room at 325 per metre square is 17550 and the cost of repairing the wall at 140 per metre square is 24080 find the dimension of the room

Answer 1

let the breadth be b
area for carpeting= 1.5b*b
cost for carpeting=325(1.5b*b)
325(1.5b*b)=17550
b=6m and length=9m

let the height of the wall be h
area for repair=length * h
cost of repair= 140(9*h) length =9m
140(9*h)=24080
h=19.11m

Answer 2

Answer:

9× 6 × 5.73

Step-by-step explanation:

Let the breadth of the room be b .

Since we are given that the length of a room is 1 and half times of its breadth

So, length of the room l = 1.5 b

Area carpeted by Rs 325 = 1 m²

Area carpeted by Rs 1 = $\frac{1}{325}$

Area carpeted with Rs 17550 = $\frac{1}{325} \times 17550$

                                                = $54$

So, The Area of the floor = 54 sq.m.

Area of floor = $Length \times Breadth = b \times 1.5 b$

So, $b \times 1.5 b =54$

$1.5 b^2 =54$

$b^2 =\frac{54}{1.5}$

$b^2 =36$

$b=6$

So,breadth of the room is 6 m.

length of the room =1.5× 6= 9 m

Let the height of the room be h m.

Area of the walls = $2h ( l + b ) = 2h ( 9+6) = 30h$

Cost of repairing the walls at Rs. 140 per sq.m. is Rs. 24080.

So, Area of walls = $\frac{24080}{ 140}$

                            = $172$

So, $30h = 172$

$h =\frac{172}{30}$

$h =5.73$

Therefore, the height of the room is 5.73 m.

Hence the dimensions of the room is 9× 6 × 5.73