Math, asked by arpanaial06, 3 months ago

The length of a room is 10 m in width 5 m and height is 5 m. The cost of installing 75 wide paper on the walls of the room is Rs. 10. What will be the total cost if per meter? (a) Rs. 1000 (b) Rs 2000 (c) Rs 3000 (d) Rs. 3500​

Answers

Answered by shaktisrivastava1234
13

 \huge \fbox{Answer}

 \large  {\underline{\frak{ \color{lime}Given:}}}

  \mapsto \sf{Length  \: of  \: room=10m}

 \mapsto \sf{Breadth \:  of  \: room=5m}

 \mapsto \sf{Height  \: of  \: room=5m}

 {\mapsto \sf{Cost \: of \: installing \: paper \: sheet \: on \: wall \: on \: 1 {m}^{2} =₹10}}

 \large  {\underline{\frak{ \color{plum}To  \: find:}}}

 {\leadsto\sf{Cost \: of \: installing \: paper \: sheet \: on \: wall.}}

 \large  {\underline{\frak{ \color{cyan}Formula \:  required::}}}

 {\boxed {\rm{Lateral  \: surface  \: area  \: of  \: room=2(length + breadth) \times height }}}

 \large  {\underline{\frak{ \color{cyn}According  \: to  \: Question:}}}

 {:: \implies{\sf{Lateral  \: surface  \: area  \: of  \: room=2(length + breadth) \times height }}}

 {:: \implies{\sf{Lateral  \: surface  \: area  \: of  \: room=2(10m + 5m) \times 5m }}}

 {:: \implies{\sf{Lateral  \: surface  \: area  \: of  \: room=2 \times 10m \times 5m }}}

 {:: \implies{\sf{Lateral  \: surface  \: area  \: of  \: room=100 {m}^{2}  }}}

 {:: \implies\sf{Cost \: of \: installing \: paper \: sheet \: on \: wall \: on \: 1 {m}^{2} =₹10}}

 {:: \implies\sf{Cost \: of \: installing \: paper \: sheet \: on \: wall \: on \: 100 {m}^{2} =₹10 \times 100}}

 {:: \implies\sf{Cost \: of \: installing \: paper \: sheet \: on \: wall \: on \: 100 {m}^{2} =₹1000}}

 \bf{Hence,Option\:(A)\:is\: correct.}

 {\boxed {\rm{ {{Cost \: of \: installing \: paper \: sheet \: on \: wall \: on \: 100 {m}^{2} =₹1000}} }}}

__________________________________________________

Answered by Anonymous
1

\huge \fbox{Answer}

Answer

\large {\underline{\frak{ \color{lime}Given:}}}

Given:

\mapsto \sf{Length \: of \: room=10m}↦Lengthofroom=10m

\mapsto \sf{Breadth \: of \: room=5m}↦Breadthofroom=5m

\mapsto \sf{Height \: of \: room=5m}↦Heightofroom=5m

{\mapsto \sf{Cost \: of \: installing \: paper \: sheet \: on \: wall \: on \: 1 {m}^{2} =₹10}}↦Costofinstallingpapersheetonwallon1m

2

=₹10

\large {\underline{\frak{ \color{plum}To \: find:}}}

Tofind:

{\leadsto\sf{Cost \: of \: installing \: paper \: sheet \: on \: wall.}}⇝Costofinstallingpapersheetonwall.

\large {\underline{\frak{ \color{cyan}Formula \: required::}}}

Formularequired::

{\boxed {\rm{Lateral \: surface \: area \: of \: room=2(length + breadth) \times height }}}

Lateralsurfaceareaofroom=2(length+breadth)×height

\large {\underline{\frak{ \color{cyn}According \: to \: Question:}}}

AccordingtoQuestion:

{:: \implies{\sf{Lateral \: surface \: area \: of \: room=2(length + breadth) \times height }}}::⟹Lateralsurfaceareaofroom=2(length+breadth)×height

{:: \implies{\sf{Lateral \: surface \: area \: of \: room=2(10m + 5m) \times 5m }}}::⟹Lateralsurfaceareaofroom=2(10m+5m)×5m

{:: \implies{\sf{Lateral \: surface \: area \: of \: room=2 \times 10m \times 5m }}}::⟹Lateralsurfaceareaofroom=2×10m×5m

{:: \implies{\sf{Lateral \: surface \: area \: of \: room=100 {m}^{2} }}}::⟹Lateralsurfaceareaofroom=100m

2

{:: \implies\sf{Cost \: of \: installing \: paper \: sheet \: on \: wall \: on \: 1 {m}^{2} =₹10}}::⟹Costofinstallingpapersheetonwallon1m

2

=₹10

{:: \implies\sf{Cost \: of \: installing \: paper \: sheet \: on \: wall \: on \: 100 {m}^{2} =₹10 \times 100}}::⟹Costofinstallingpapersheetonwallon100m

2

=₹10×100

{:: \implies\sf{Cost \: of \: installing \: paper \: sheet \: on \: wall \: on \: 100 {m}^{2} =₹1000}}::⟹Costofinstallingpapersheetonwallon100m

2

=₹1000

\bf{Hence,Option\:(A)\:is\: correct.}Hence,Option(A)iscorrect.

{\boxed {\rm{ {{Cost \: of \: installing \: paper \: sheet \: on \: wall \: on \: 100 {m}^{2} =₹1000}} }}}

Costofinstallingpapersheetonwallon100m

2

=₹1000

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