the length of a room is 3 times its height and breadth is 3/2times its height the cost of whitewashing the wall @ Rupees 1.50 per square metre is rupees 16 find the dimensions of the room
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Solution :-
There is a mistake in the question. I think the total cost of whitewashing the four walls of the room must be Rs. 216 instead of Rs. 16.
Let the height of the room be x meters
Then, the length will be 3x meters and the breadth will be 3x/2 meters
Now, Total cost of whitewashing the four wall is Rs. 216 and the cost of whitewashing is Rs. 1.50 per square meter.
Therefore, the painted area = 216/1.5
= 144 sq m
So, the area of the four walls is 144 sq m
Lateral Surface Area of Cuboid = 2H(L + B)
⇒ 2x(3x + 3x/2)
⇒ 2x(6x + 3x)/2
⇒ 2x*(9x/2)
⇒ 18x²/2 = 144
⇒ 9x² = 144
⇒ x² = 144/9
⇒ x² = 16
⇒ x = √16
⇒ x = 4 m
Height is 4 m
So, length = 12 m and breadth = (4*3)/2 = 6 m
Answer.
There is a mistake in the question. I think the total cost of whitewashing the four walls of the room must be Rs. 216 instead of Rs. 16.
Let the height of the room be x meters
Then, the length will be 3x meters and the breadth will be 3x/2 meters
Now, Total cost of whitewashing the four wall is Rs. 216 and the cost of whitewashing is Rs. 1.50 per square meter.
Therefore, the painted area = 216/1.5
= 144 sq m
So, the area of the four walls is 144 sq m
Lateral Surface Area of Cuboid = 2H(L + B)
⇒ 2x(3x + 3x/2)
⇒ 2x(6x + 3x)/2
⇒ 2x*(9x/2)
⇒ 18x²/2 = 144
⇒ 9x² = 144
⇒ x² = 144/9
⇒ x² = 16
⇒ x = √16
⇒ x = 4 m
Height is 4 m
So, length = 12 m and breadth = (4*3)/2 = 6 m
Answer.
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