Question

The length of a room is 6m and the length is twice the breadth. if the area of the floor is 162m2, find the area of the four walls of the room.

Answer 1

l = 6m

b= 3m

Height of the wall is not given

Answer 2

Answer:

324m^2

Step-by-step explanation:

Let l, b, h be the length, breadth and height of the room respectively.

Given h= 6m. and l=2b.

Area of the floor =lb =162

2b^2 = 162

since l=2b

b^2 = 81

b = 9m, l =18m, h =6m.

Area of four walls= 2h(l + b)

= 2×6(18+9) = 12×27 = 324m^2