the length of a rope, to which a cow is tied, is increased from 19m to 30m. assuming that the cow is able to move on all sides with equal ease, the additional ground it will be able to graze is:
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since a cow is tied to a rope so cow can graze in a circular range.
so first we find the previous area I.e.
πr^2
=22/7×19×19
=1134.57m^2. (1)
now we find the area when rope is increased
πr^2
=22/7×30×30
=2828.57m^2. (2)
now we subtract from equation 1 to 2
2828.57-1134.57
=1694m^2
now the cow can graze1694m^2 more ground
if you satisfied with my answer please mark me
so first we find the previous area I.e.
πr^2
=22/7×19×19
=1134.57m^2. (1)
now we find the area when rope is increased
πr^2
=22/7×30×30
=2828.57m^2. (2)
now we subtract from equation 1 to 2
2828.57-1134.57
=1694m^2
now the cow can graze1694m^2 more ground
if you satisfied with my answer please mark me
nknavaneethan2:
thanks with salute
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4
This is u r answer mark as brainlist answer
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