Question

the length of a second pendulum is 1 m [ where g = 9.8 m/s² ]. what will be the length of second pendulum on any planet where g = 9.8 m/s² ?

Answer 1

The length of the second pendulum will be 1m
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Answer 2

Answer:

The length of a seconds' pendulum is $1m$ [ where g = 9.8 m/s² ]. The length of the seconds' pendulum on any planet where g = 9.8 m/s² is $1m$ only  

Explanation:

The seconds' pendulum is a type of pendulum whose time period is two seconds that is $T=2s$

For a normal pendulum with the length, $l$ the time period is given by the formula

$T=2\pi \sqrt{\frac{l}{g} }$

By rearranging the equation to get the length of the seconds' pendulum

$l=g/\pi ^{2}$

From the question acceleration due to gravity is $g=9.8m/s^{2}$

therefore the length of the pendulum is $l=9.8/\pi ^{2} =1m$

The length depends only on the value of acceleration due to gravity so wherever on the planet if $g=9.8m/s^{2}$ the length would be $l=1m$ only