Question

The length of a second pendulum is double. What happen to the time period of the pendulum?

Plz, do it quickly. It's urgent.

Answer 1

Time period of pendulum = 2π√(L/g)

We can see that time period is proportional to √L.

For a seconds pendulum,
Time period(T) = 2 sec
Length (L) = L

After doubling the length
Length (L')= 2L
Time period = T'

T'/T = √(L'/L)

Or T' = T × √(L'/L)

Or T' = 2 × √2

Or T' = 2√2 sec

The new time period will be 2√2 second.

So what will happen is,
- The time period will increase.
- The time period will be √2 times the original time period.
- The new time period will be 2√2 second.

Choose your answer whichever is required.

Hope it helps!:)

Answer 2

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Time period of pendulum = 2π√(L/g)

We can see that time period is proportional to √L.

For a seconds pendulum,

Time period(T) = 2 sec

Length (L) = L

After doubling the length

Length (L')= 2L

Time period = T'

T'/T = √(L'/L)

Or T' = T × √(L'/L)

Or T' = 2 × √2

Or T' = 2√2 sec

The new time period will be 2√2 second.

So what will happen is,

- The time period will increase.

- The time period will be √2 times the original time period.

- The new time period will be 2√2 second.