the length of a side of a square field is 4 m. what will be the altitude of the rhombus, if the area of the rhombus is equal to the square field and one of its diagonals is 2 m?
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Area of square is 16
now,area of rhombus is 1/2* base *height
where base is 4 and area of rhombus is equal to square
Therefore, 16=1/2*4*h
16=2h
h=16/2
=8 is the altitude
now,area of rhombus is 1/2* base *height
where base is 4 and area of rhombus is equal to square
Therefore, 16=1/2*4*h
16=2h
h=16/2
=8 is the altitude
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