The length of a side of a square field is 4 m. What will be the altitude of a rhombus whose area is equal to the square field and one of its diagnols is 2m long?
Answers
Answered by
3
Step-by-step explanation:
The length of a side of a square field is 4 m. What will be the altitude of the rhombus, if the area of the rhombus is equal to the square field and one of its diagonals is 2 m?
Simplify your business purchases with Amazon Business.
Area of the square field = (4 * 4) sq metres = 16 sq metres.
Area of the rhombus = 16 sq metres.
One diagonal of the rhombus = 2 metres
Let, the other diagonal of the rhombus be x metres.
Area of the rhombus = {(x * 2) / 2} sq metres = x sq metres.
So, x = 16.
Therefore, diagonals of the rhombus are of 2 metres and 16 metres; and they are perpendicular bisectors of one another.
Each side of the rhombus = √{(1^2) + (8^2)} metres = √65 metres.
Altitude of the rhombus = (16 / √65) metres.
Similar questions