the length of a side of a square field is 4m.What will be the altitude of the rhombus,if the area of the rhombus is equal to the square field and one of its diagonal is 2 m?
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Step-by-step explanation:
The area of square is side square that is 4square =4x4=16m square
Area of rhombus is half the product of its diagnols
1 diagnosed is 2m
Let the other be x
1/2 of (X x 2) = 16
(X x 2) = 16 x 2
(X x 2) = 32
X=32/2
X=16
It’s other diagonal is 16m
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