Math, asked by KYOTO7OYKOT, 9 months ago

The length of a side of a square is represented by (3x − 1) units. If the perimeter of the square is 68 units, what is the value of x?

Answers

Answered by HashtagNoName
0

Answer:

Perimeter = 4*side

side = Perimeter/4

3x - 1 = 68/4 = 17

3x = 17 + 1 = 18

x = 18/3 = 6

x is equal to 6 units

Answered by ashish564181
2

Step-by-step explanation:

Hello

First., since side of square is [3x-1]

And perimeter is 68

Then,

Sum of all side of square =Perimeter of the square

Note:all side of square are same

[3x-1]+[3x-1]+[3x-1]+[3x-1]=68

4[3x-1]=68

[3x-1]=68/4

3x-1=17

X=17+1

3x=18

X=18/3

X=6

Good day

X=6

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