Question

The length of a side of a triangle are in the ratio 3:4:5 find the area of the triangle if its perimeter is 48cm

Answer 1

12x=84
so,
x=7
so
sides=3,4,5.
therefore,
semiperimeter=3+4+5/2=12/2=6
therefore,
by herons formula,
area=
$6(6 - 3)(6 - 4)(6 - 5) = 6 \times 3 \times 2 \times 1 = 26$

that is, 26cm2

Answer 2

Hey mate here is your answer :::

Given -
Ratio of triangle = 3:4:5

So,
Let the first side of ∆ be 3X
Let the second side of ∆ be 4X
Let the third side of ∆ be 5X

According to the question (A.T.C.)

3x+4x+5x=48
12x=48
X=48/12
X=4

Therefore,
the first side of ∆ = 3X= 3(4)=12cm
The second side of ∆ = 4X=4(4)=16cm
The third side of ∆ =5X=5(4)=20 cm

AREA ----------

area of ∆ = 1/2*base *height
area=1/2*