the length of a side of an equilateral triangle is 21 cm what would be the approximate area of the circumcircle of the above triangle
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from the figure attached with this,the large triangle is an equilateral triangle with each angle 60°. AC bisect ∠A. So ∠CAB=30° , ∠ACB=60° and ∠ABC=90°
ΔABC is a right triangle with angles 30°,60° and 90°
BC:AB:AC=1:√3;2
AB= 10.5
we get radius of circumcircle, r= AC = 21/√3
area of circumcircle A = π r^2 = 3.14 x (21/√3 )^2 = 462 cm^2
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