Question

the length of a simple pendulum executing SHM is increased by 21% the percentage increase in the time period of the pendulum of incresed length is

Answer 1

Answer:

Hey mate here is your answer.//

Explanation:

Solution :

Time period of a simple pendulum is ,

T=2πlg−−√ or T∝l1/2 or T=kl1/2 ,

ΔTT=12Δll Given Δll×100=21% ,

% increase in time period ,

=ΔTT×100=12/Δll×100=12×21%=10.5%,

hope it helps you,//

sorry if too complicated but the anwer is 10.5 %,//

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