Question

the length of a simple pendulum is decreased by 10%. What effect will it have on the frequency of the pendulum.please explain with solution

Answer 1

T = 2 π sqrt(L / g) = 1/f

f^2 ∝ 1/L

(f1/f2)^2 = (L2/L1)
[(100) / (100 + x)]^2 = (90 / 100)
(100 + x)^2 = (10000 / 0.9)
100 + x = 105.4
x = 105.4 - 100
x = 5.4

Frequency will increase by 5.4%