Physics, asked by ashok20, 1 year ago

The length of a smooth inclined plane of inclination 30 degree is 5m. The work done in moving a 10 kg mass from the bottom of the inclined plane to top is

Answers

Answered by einsteinvimal

5

F - mgsin30 = mg
F = 150N
W= 150 × 5
= 750J

Answered by ujwalkarthikeyauk

0

Answer:

250J

Explanation:

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