The length of a sonometer wire AB is 100 cm. Where should the two bridges be placed from A to divide the wire in 3
segments whose fundamental frequencies are in the ratio of 1
(A) 30 cm, 90 cm
(B) 60 cm, 90 cm
(C)
40 cm, 80 cm
(D) 20 cm, 30 cm
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Answer:
B
Explanation:
answer is 60 cm,90 cm
because from the law of vibration f1.L1=F2=L2=F3=L3
so that we find the answer 60vm and 90cm
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